lim x-->tak hingga
[tex]((3x - 2) - \sqrt{9 {x}^{2} - 2x + 1) } [/tex]
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[tex]((3x - 2) - \sqrt{9 {x}^{2} - 2x + 1) } [/tex]
Jawaban:
limit (3x - 2) - √(9x² - 2x + 1)
x-->∞
limit √(3x - 2)² - √(9x² - 2x + 1)
x-->∞
limit √(9x² - 12x + 4) - √(9x² - 2x + 1)
x-->∞
gunakan rumus
limit √(ax² + bx + c) - √(px² + qx + r)
x-->∞
a > p ---> x = ∞
a < p ---> x = -∞
a = p ---> x = (b - q)/2√a
pada soal diatas a = p = 9
maka
x = [(-12 - (-2)]/2√9
x = (-10)/2(3)
x = -10/6
x = -5/3
" maaf kalau salah "
[answer.2.content]
